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Q: How can you make 46 a product of prime factor tree method?

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As a product of its prime factors: 3*5*7 = 105

First, make sure all the factors are, in fact, prime. Then make sure that the product of all the factors is the number you wanted to factor.

Not a lot. They're both prime numbers. A factor that is prime is used to make other numbers.

A product (multiple) is divisible by a factor (divisor)

As a product of its prime factors: 2*23 = 46

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As a product of its prime factors: 3*5*7 = 105

As a product of its prime factors: 2*2*7*7 = 196

As a product of its prime factors: 2*2*5*5 = 100

As a product of its prime factors: 2*2*2*5*7 = 280

First, make sure all the factors are, in fact, prime. Then make sure that the product of all the factors is the number you wanted to factor.

NO!!! Because the two factors that make '10' are '2' & '5' . Both '2' & '5' are prime factors.

Not a lot. They're both prime numbers. A factor that is prime is used to make other numbers.

Small words make a difference. No prime number "has" a factor of 16. But 2 is the only prime number that "is" a factor of 16.

You don't. 41 is a prime number. Prime numbers don't have factor trees, since they only have one prime factor.

7 is a prime number; its only prime factor is 7.

how can exponent can make it easier to write an expression with a repeated factor in the product

Any two.

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