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600 divisble by:2 it is even3 the sum of digits is a multiple of 3 (6 + 0 + 0 = 6)4 the last two digits is a multiple of 45 it ends with 0 or 56 it is divisible by 2 and 38 the last three digits is multiple of 810 it is ends with 0
Without repeating digits (not digets!) and without leading 0s, 600 of them.
The highest number you can make out of the digits 2 4 0 and 1 is 4210.
∞ \ Infinite
You need to make sure that there are six more digits after the "152". Fill out missing digits with 0.