I don't know about proving it arithmetically, but graphically you can prove it really easily.
Draw a circle, and just focus on one portion of the circle's curve. Keep making its radius bigger, looking at the same section of the circle. You'll see the curve gets wider and wider. If you kept going, the curve would get so wide it would start getting closer to a line shape. So in theory, if you made the radius infinite, it would reach the point where the curve becomes so wide it's just a straight line.
A circle is NOT made up of straight lines. As the number of sides of an n-gon are increased and the length of each side is reduced, the distance between the n-gon and the circle can be made smaller than an arbitrarily small number. The n-gon TENDS to the circle as the length of the largest straight line segment tends to zero but that does not mean the two are ever the same.
There is no mathematical proof that space is infinite. All we know is that there is an expanding limit to what we can see.
You could draw a circle [center at origin] with radius of (a + b), for the two magnitudes a and b. This represents the sum of the magnitudes. Then draw one of the vectors starting at the origin [suppose it's vector a], and then draw a circle centered at the endpoint of vector a, with a radius of b. Drawing a circle demonstrates how the second vector can point in any direction relative to the first vector. The distance from the origin to a point on this second circle is the magnitude of the resultant vector. Graphically this second circle will be entirely inside the first circle and touching it at just one point. Since it lies within the first circle, the distance from the origin to a point on that circle will be less than or equal to the radius of the first circle.
Step I: Show that both points are outside the smaller circles. Possibly by showing that distance from each point to the centre of the circle is greater than its radius. Step 2: Show that the line between the two points touches the circle at exactly one point. This would be by simultaneous solution of the equations of the line and the circle.
Chuck Norris can prove it
The diameter of a circle is its line of symmetry and the lines can be infinite
Ah, infinite sides, what a beautiful concept! You see, my friend, a circle is the polygon with infinite sides. As you keep adding more and more sides to a polygon, it starts to look more like a circle. Just imagine the gentle curves of a circle, embracing all those infinite sides with love and kindness.
It is not true because the distance from (0, 0) to (2, 1) works out as the square root of 5 which is the circle's radius.
Continue or follow the inner or outer trajectory of the radius arc line in either, or both, directions until it meets itself. The i will have a center point which is at a fixed distance from the arc, equal to one half of the radius of the finished circle, and which will thereby prove the circle.
Make a diagram. One way to define sine and cosine is with the unit circle - a circle with a radius of 1 unit. For any point on the circle, the sine is the y-component, while the cosine is the x-component.
A circle is NOT made up of straight lines. As the number of sides of an n-gon are increased and the length of each side is reduced, the distance between the n-gon and the circle can be made smaller than an arbitrarily small number. The n-gon TENDS to the circle as the length of the largest straight line segment tends to zero but that does not mean the two are ever the same.
To prove the formula you need to integrate the function y = +sqrt(1 - x2) between the limits x = -1 and x = +1, and then double the result to allow for the area under the x-axis. Better still, use polar coordinates and double integrate rdrdA where r goes from 0 to R, the radius of the circle, and the angle A goes from 0 to 2*pi. The result can be VERIFIED by comparing the area and the radius but that is not proof.
There is no mathematical proof that space is infinite. All we know is that there is an expanding limit to what we can see.
By definition, the number of radians in one complete revolution is given by the ratio of the circumference of a circle to its radius. The circumference of a circle of radius r is of length 2πr. There are thus 2πr/r = 2π radians in one revolution. So, 2π radians = 360° Then 1 radian = 360/2π = 57.296° or 57° 17'
You could draw a circle [center at origin] with radius of (a + b), for the two magnitudes a and b. This represents the sum of the magnitudes. Then draw one of the vectors starting at the origin [suppose it's vector a], and then draw a circle centered at the endpoint of vector a, with a radius of b. Drawing a circle demonstrates how the second vector can point in any direction relative to the first vector. The distance from the origin to a point on this second circle is the magnitude of the resultant vector. Graphically this second circle will be entirely inside the first circle and touching it at just one point. Since it lies within the first circle, the distance from the origin to a point on that circle will be less than or equal to the radius of the first circle.
He is straight he has a kid that should prove it.
Simply by measuring it. Or by drawing a circle with a radius of half the hypotenuse and having the vertex of the right angle as its centre and if the midpoint of the hypotenuse just touches the circle then this proves it.