I don't think you wanted the word "radical" in your question. Aren't you working with: C2 = A2 + B2 ? Or maybe: C = sqrt ( A2 + B2 ) ? In either case, A = sqrt ( C2 - B2 ). If your question is really the way you typed it, then the answer is more complicated.
It is sqrt(0), which equals 0.
The square root of six divided by the square root of two equals the square root of three.
Basically, each number is the square root of its square. So, if you square 59, the result will tell you what number you need to take the square root of, to get 59.
5 radical 100 can be expressed mathematically as 5 times the square root of 100. Since the square root of 100 is 10, this simplifies to 5 times 10, which equals 50. Therefore, 5 radical 100 is equal to 50.
If the product of two irrationals is a rational, then they are both the same radical of a non-perfect square. For example, radical 5 times radical 5 is 5, since that is by definiton what a radical is.
It is sqrt(0), which equals 0.
The square root of 136 would be broken up into radical 4 and radical 34, because 4 is the highest perfect square that goes into 136 evenly, and radical 4 equals 2. So, your final answer would be 2 radical 34.
The square root of six divided by the square root of two equals the square root of three.
Basically, each number is the square root of its square. So, if you square 59, the result will tell you what number you need to take the square root of, to get 59.
The square root of 149 in radical form is √149. This means that the number that, when multiplied by itself, equals 149 is the square root of 149. The square root of 149 is an irrational number, as it cannot be expressed as a simple fraction.
The square-root of B2 is +B and also -B .
There is no "radical square root". Radical means the same as root, it may specifically refer to the square root.
You can factor out the Root(16) which equals 4. So the answer is 4 Root(2).
You can factor out the Root(16) which equals 4. So the answer is 4 Root(3).
If the product of two irrationals is a rational, then they are both the same radical of a non-perfect square. For example, radical 5 times radical 5 is 5, since that is by definiton what a radical is.
If the radical is the square root of a quantity, then yes.
Sqrt[5*radical(68)] = -6.4211 and +6.4211.