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3 times 8 it's only 24 always

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13y ago

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Related Questions

How can you use a 2s fact and 1s fact to find 3 times 8?

3 * 8 = (2 + 1)*8 = (2 * 8) + (1 * 8)


How can you use a 2s fact and a 1sfact to find 3x8?

To find 3x8 using a 2s fact and a 1s fact, you can decompose the multiplication. For example, you know that 2x8 equals 16 (a 2s fact), and you also know that 1x8 equals 8 (a 1s fact). You can then use these to find 3x8 by adding 2x8 and 1x8 together: 16 (from 2x8) + 8 (from 1x8) equals 24, which is the answer for 3x8.


How can use a 2s fact and a 1s fact to find 3 x 8?

To find 3 x 8 using a 2s fact and a 1s fact, you can break down 8 into manageable parts. For instance, you know that 3 x 2 = 6 (a 2s fact) and 3 x 1 = 3 (a 1s fact). Then, you can combine these to find 3 x 8 by calculating 3 x (2 + 2 + 2) = 3 x 2 + 3 x 2 + 3 x 2, which equals 6 + 6 + 6 = 24. Alternatively, you can also use 3 x 4 (2s fact) and double it to get 24.


How can you use a 2s fact and 1s fact to find 3x8?

(1 x 3 ) x ( 2 X 4) = 24


How can you use a 2s fact and a 1s fact to find 3x8?

3x8 with1s and 2s fact looks like this: =(2x8)+(1x8) =16+8 =24


How can you use 1s and 2s facts to find 3x7?

I think 7x3 is = to 21


How can you use 2s and 1s facts to find 3x8?

To find (3 \times 8) using 2s and 1s facts, you can break it down into simpler components. First, recognize that (8) can be expressed as (4 + 4), so (3 \times 8) can be rewritten as (3 \times (4 + 4)). This gives you (3 \times 4 + 3 \times 4). Since (3 \times 4 = 12), you can add (12 + 12) to get (24). Thus, (3 \times 8 = 24).


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