You don't need to use the distributive property.
3*17 = 51 so 30*17 = 510
Why invoke procedures that are not necessary?
No.
You can use the distributive property of multiplication to find the product. (a) 5 x 6 = 30 (b) 6 x 6 = (5 + 1) x 6 (c) 6 x 6 = 5 x 6 + 1 x 6 by the distributive property (d) 6 x 6 = 30 + 1 x 6 by substituting equation (a) (e) 6 x 6 = 30 + 6 by the identity property of multiplication (f) 6 x 6 = 36
no because distributive property is for multiple digit numbers.
No, it is not.
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49
Some people use the distributive property to add 24 and 36, but you wouldn't use it to find the GCF which, by the way, is 12.
To use the distributive property to find the product of 9 times 504, you can break down 504 into smaller, more manageable parts. For example, you can express 504 as 500 + 4. Then, apply the distributive property: (9 \times 504 = 9 \times (500 + 4) = (9 \times 500) + (9 \times 4)). Calculate each part: (9 \times 500 = 4500) and (9 \times 4 = 36), so the total is (4500 + 36 = 4536).
(7 x 10) + (7 x 4) + (7 x 0.6) = 70 + 28 + 4.2 = 102.2
One way is: 15 * 104 = 15*(100 + 4) = 15*100 + 15*4 = 1500 + 60 = 1560
according to commutative property both the distributive laws are equal why to use two distributive laws
No.
distributive property for (11-3)=
First, I would find that the GCF of 20 and 16 is 4. Then, I would divide both 20 and 16 by 4. Last, I would use the distributive property to write the sum as 4(5 + 4).
You can use the distributive property of multiplication to find the product. (a) 5 x 6 = 30 (b) 6 x 6 = (5 + 1) x 6 (c) 6 x 6 = 5 x 6 + 1 x 6 by the distributive property (d) 6 x 6 = 30 + 1 x 6 by substituting equation (a) (e) 6 x 6 = 30 + 6 by the identity property of multiplication (f) 6 x 6 = 36
no because distributive property is for multiple digit numbers.
No, it is not.