There are many ways to answer this question. One way:
45 times 3 is 135 so 135 is a multiple of 3.
-- If you drop beans into a bag 3 at a time, there will
never be 134 or 136 beans in the bag, but there will be
a moment when there are exactly 135 beans in there.
-- If you divide 133 or 137 by 3, there will be a remainder,
because they're not multiples of 3. But if you divide 135 by 3,
there will be no remainder, because 135 is a multiple of 3.
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Yes. Because 135 is divisible by both 3 an 5, that is 135 can be divided by both 3 and 5 with no remainder.
Since 135 is a multiple of 15, it is automatically the LCM of this problem.
For any two natural numbers a & b: Their LCM is b if b is the multiple of a. Here, 135 is the multiple of 27(27 x 5 = 135). Therefore, LCM of 27 & 135 = 135.
The Least Common Multiple (LCM) for 36 60 135 is 540.
No, 7 cannot be divided evenly into 135.