There are many ways to answer this question. One way:
45 times 3 is 135 so 135 is a multiple of 3.
-- If you drop beans into a bag 3 at a time, there will
never be 134 or 136 beans in the bag, but there will be
a moment when there are exactly 135 beans in there.
-- If you divide 133 or 137 by 3, there will be a remainder,
because they're not multiples of 3. But if you divide 135 by 3,
there will be no remainder, because 135 is a multiple of 3.
Yes. Because 135 is divisible by both 3 an 5, that is 135 can be divided by both 3 and 5 with no remainder.
Since 135 is a multiple of 15, it is automatically the LCM of this problem.
For any two natural numbers a & b: Their LCM is b if b is the multiple of a. Here, 135 is the multiple of 27(27 x 5 = 135). Therefore, LCM of 27 & 135 = 135.
The Least Common Multiple (LCM) for 36 60 135 is 540.
No, 7 cannot be divided evenly into 135.
Yes. Because 135 is divisible by both 3 an 5, that is 135 can be divided by both 3 and 5 with no remainder.
135
The Least Common Multiple (LCM) of (3,15,27) is 135.
The lowest common multiple of these 3 numbers (besides from 1) is 5.
The least common multiple of the numbers 27, 45 and 135 is 135.
The Least Common Multiple (LCM) for 15 27 is 135.The least comon multiple of 15 and 27 is 135.
No, 5 is a factor of 135.
Since 135 is a multiple of 27, it is automatically the LCM.
The LCM is: 135
well, it could be 1... (for any two numbers) but besides that it would be 3 (since we could tell that 2 isn't a multiple in either 135 or 225)
Least common multiple of 30 and 135 is 270.
Since 135 is a multiple of 15, it is automatically the LCM of this problem.