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V1 = (1/3)(pi)(r12)(h1)

V2 = (1/3)(pi)(xr12)(h2)

V1 = V2 , which means that:

(1/3)(pi)(r12)(h1) = (1/3)(pi)(xr12)(h2)

Divide both sides by (1/3)(pi) and you get:

(r12)(h1) = (xr12)(h2)

-> (r12)(h1) = x2(r12)(h2)

Divide both sides by (r12) and you get:

h1 = x2(h2)

-> h2 = (h1)/x2

For example: Cone1: r1 = 10, h1 = 10

Cone2: r2 = 30, h2 = (10/32) = 10/9 = 1.11111111

Then to check: Volume of a cone = (1/3)(pi)(r2)(h)

V1 = (1/3)(pi)(102)(10)

V1 = 1047.197551 = V2

1047.197551 = (1/3)(pi)(302)(h2)

h2 = 1047.197551/((900pi)/3)

h2 = 1.111111111 = 10/9

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Q: How could you change the height of a cone so that its volume would remain the same when its radius was tripled?
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