V1 = (1/3)(pi)(r12)(h1)
V2 = (1/3)(pi)(xr12)(h2)
V1 = V2 , which means that:
(1/3)(pi)(r12)(h1) = (1/3)(pi)(xr12)(h2)
Divide both sides by (1/3)(pi) and you get:
(r12)(h1) = (xr12)(h2)
-> (r12)(h1) = x2(r12)(h2)
Divide both sides by (r12) and you get:
h1 = x2(h2)
-> h2 = (h1)/x2
For example: Cone1: r1 = 10, h1 = 10
Cone2: r2 = 30, h2 = (10/32) = 10/9 = 1.11111111
Then to check: Volume of a cone = (1/3)(pi)(r2)(h)
V1 = (1/3)(pi)(102)(10)
V1 = 1047.197551 = V2
1047.197551 = (1/3)(pi)(302)(h2)
h2 = 1047.197551/((900pi)/3)
h2 = 1.111111111 = 10/9
V = (pi) R^2 H/3 if radius triples then volume goes as radius squared = 9 times more, so you would need to reduce height by 9 to keep same volume
It must be made a third of its current value, ie divided by 3. The volume of a pyramid is 1/3 x area_base x height. The 1/3 is constant; to keep the volume constant as the base_area changes, the height must vary inversely. If the base_area is tripled, ie multiplied by 3, the height must be reduced to a third, ie divided by 3.
You cannot. If you rotate the circle around its centre, the lengths of the radius and chord will remain the same but the coordinates of the chord will change.
I'd need to review what happened in number-1 before I could answer that. I do know that if only the length of a rectanguar prism is tripled, while the other two dimensions remain unchanged, then its volume triples.
Nothing - if you double the radius you will get the diameter. The area of the circle will remain the same
V = (pi) R^2 H/3 if radius triples then volume goes as radius squared = 9 times more, so you would need to reduce height by 9 to keep same volume
It must be made a third of its current value, ie divided by 3. The volume of a pyramid is 1/3 x area_base x height. The 1/3 is constant; to keep the volume constant as the base_area changes, the height must vary inversely. If the base_area is tripled, ie multiplied by 3, the height must be reduced to a third, ie divided by 3.
young modulus remain unaffected ...as it depends on change in length ..
You cannot. If you rotate the circle around its centre, the lengths of the radius and chord will remain the same but the coordinates of the chord will change.
I'd need to review what happened in number-1 before I could answer that. I do know that if only the length of a rectanguar prism is tripled, while the other two dimensions remain unchanged, then its volume triples.
No - if the lengths of the sides are all increased by a factor of 3, the angles remain unchanged. You just wind up with a "similar" triangle 3 times the size of the original. A quick counterexample would be to consider what would happen if the angles DID change. The sum of the angles in the original triangle should be 180°. If the angles in the new, larger triangle tripled in size, the sum of the angles in the bigger triangle would be 540° - but the sum of the angles of a triangle should always remain 180°.
Nothing - if you double the radius you will get the diameter. The area of the circle will remain the same
The surface area of the 'wall' doubles, but the base areas remain the same.
The height would remain the same.
If velocity is tripled, the kinetic energy of an object will increase by a factor of nine. This is because kinetic energy is directly proportional to the square of the velocity according to the equation KE = 0.5 * m * v^2.
remain the same
Substance in the material Remain the same