To calculate the slope of the trend line, I used the formula ( m = \frac{(N \sum xy) - (\sum x)(\sum y)}{(N \sum x^2) - (\sum x)^2} ), where ( N ) is the number of data points, ( \sum xy ) is the sum of the product of each pair of x and y values, ( \sum x ) is the sum of the x values, ( \sum y ) is the sum of the y values, and ( \sum x^2 ) is the sum of the squares of the x values. This formula derives from the least squares method, which minimizes the distance between the actual data points and the trend line. After computing the necessary sums, I substituted them into the formula to find the slope.
the slope of a vertical line is 0.
trend line
The slope of the line y = -2 is zero.
A trend line.
it compares with people By the way this is mr. moles so dont cheat online
the slope of a vertical line is 0.
trend line
The slope of the line y = -2 is zero.
A trend line.
A major problem in projecting with a trend line is that
it compares with people By the way this is mr. moles so dont cheat online
Two coordinates are needed to work out the slope of the line.
Find the value of the trend line when x = 0
What is the difference between a trend line and a line of best fit
1.5
It is the intercept.
It is the rise/run for the line.