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In that case, you must use what is given.

For example, if the circumference is given, then the diameter is [ C / pi ] .

If, instead, the area is given, then the diameter is [ 2 sqrt( A / pi ] .

In any problem-solving situation, fretting about what you don't have

doesn't get you anywhere. Just relax, and use what you dohave.

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13y ago

What else can I help you with?