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You multiply one equation by some constant, or both equations by different constants, and then add one equation to another (or subtract). Here is an example:
2x + 4y = 30
x + y = 10
Multiplying the second equation by (-2), you get:
2x + 4y = 30
-2x -2y = -20
Now you can add the two equations together, resulting in:
2y = 10
You can solve this for "y"; then you can replace the value you found in any of the original equations to find the corresponding value for "x".
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What are the ways to solve a system of linear equations in two variables?
the substitution method in which you take each variable and you find out the value and then plug it into the original equation.the adding and subtracting method in which you subtract\add equations to take out a variable and you can figure out what the other variable is. then you also substitute that into that into the original variable
Solve linear equations with complex coefficients on both sides?
You would solve them in exactly the same way as you would solve linear equations with real coefficients. Whether you use substitution or elimination for pairs of equations, or matrix algebra for systems of equations depends on your requirements. But the methods remain the same.
How do you work a simultaneous equation?
You cannot work a simultaneous equation. You require a system of equations. How you solve them depends on their nature: two or more linear equations are relatively easy to solve by eliminating variables - one at a time and then substituting these values in the earlier equations. For systems of equations containing non-linear equations it is simpler to substitute for variable expression for one of the variables at the start and working towards the other variable(s).
What is the basic rules to solve equations?
The basic rules to solve equations are to isolate the variable on one side of the equation by performing the same operation on both sides. This includes adding or subtracting the same value, multiplying or dividing by the same value, and applying exponent or logarithm rules if necessary. The goal is to simplify the equation until the variable is alone on one side and the solution can be determined.
How do you solve systems of equations using substitution?
3(5x-2y)=18 5/2x-y=-1
