[(aXbXc)X(dXeXf)]X[(aXbXc)X(dXeXf)]X[(aXbXc)X(dXeXf)]
3 times 17
The prime factorization of 225 is (3^2 \times 5^2). To express this as a product of four prime numbers, we can write it as (3 \times 3 \times 5 \times 5). Thus, the four prime numbers that multiply to make 225 are 3, 3, 5, and 5.
How about 3 times 3 = 9 as one example
The product for 3 times 9 is 27. Product is the answer you get when you multiply numbers together.
47 times 3
you multiply 2 plus 3 than 23 times 3
3 times 17
The prime factorization of 225 is (3^2 \times 5^2). To express this as a product of four prime numbers, we can write it as (3 \times 3 \times 5 \times 5). Thus, the four prime numbers that multiply to make 225 are 3, 3, 5, and 5.
How about 3 times 3 = 9 as one example
The product for 3 times 9 is 27. Product is the answer you get when you multiply numbers together.
47 times 3
How about: 3 times -6 = -18 as one example
252
To square a number you multiply it by itself, to cube a number you then multiply itself twice! i.e. 3 times 3 is 9 and 9 times 3 is then 27 so 27 is 3 cubed
You can multiply the numbers 4, 4, and 4 to get 64, since (4 \times 4 \times 4 = 64). Alternatively, you could use the numbers 2, 4, and 8, as (2 \times 4 \times 8 = 64) as well.
11754
They are: 3 times 11 = 33