molecular weight of NiSO4.7H2O is 1101.3 and it has 11 oxygens.
So percentage of oxygen = (7 x 16) / 1101.3 = 112 / 1101.3 = 0.102 or 10.2%
The compound is called nickel sulfate heptahydrate.
62.816
44.9
The compound NiSO4·7H2O consists of one NiSO4 molecule and seven water molecules. The percentage of water can be calculated by dividing the molar mass of water by the molar mass of the whole compound, and then multiplying by 100. This results in about 37.2% water in NiSO4·7H2O.
The relative molecular weight of the compound nickel (II) sulphate heptahydrate NiSO4 7H2O is 280. 86. The total mass of oxygen in the compound is 176 g. Therefore the total percentage of oxygen to the nearest tenth is 60 percent
The compound NiSO4 7H2O is magnesium sulfate heptahydrate. It is a type of inorganic salt that is commonly known as Epsom salt.
The chemical formula for nickel II sulfate hexahydrate is NiSO4•6H2O. It consists of one nickel (Ni) atom, one sulfur (S) atom, four oxygen (O) atoms, and six water (H2O) molecules.
The formula given is mgSO4 * 7H2O. This means there are 4 oxygen atoms in MgSO4 and 14 oxygen atoms in 7H2O, giving a total of 18 oxygen atoms in the entire formula.
The compound name for 7H2O is heptahydrate.
The formula for ferrous sulfate is FeSO4.6-7H2O. (Iron Sulfate + Water) (Iron, Sulfur, Oxygen, + Hydrogen, Oxygen) No, it does not contain carbon.
To calculate the percent of water in FeSO4·7H2O, you need to consider the molecular weights of each component. The molecular weight of FeSO4 is 151.91 g/mol, and the molecular weight of 7H2O is 126.14 g/mol. The total molecular weight of FeSO4·7H2O is 277.05 g/mol. The percent of water in FeSO4·7H2O is (126.14/277.05) x 100 = 45.5%.
The cation of MgSO4·7H2O is Mg^2+ (magnesium ion).