molecular weight of NiSO4.7H2O is 1101.3 and it has 11 oxygens.
So percentage of oxygen = (7 x 16) / 1101.3 = 112 / 1101.3 = 0.102 or 10.2%
The compound is called nickel sulfate heptahydrate.
62.816
44.9
The compound NiSO4·7H2O consists of one NiSO4 molecule and seven water molecules. The percentage of water can be calculated by dividing the molar mass of water by the molar mass of the whole compound, and then multiplying by 100. This results in about 37.2% water in NiSO4·7H2O.
The relative molecular weight of the compound nickel (II) sulphate heptahydrate NiSO4 7H2O is 280. 86. The total mass of oxygen in the compound is 176 g. Therefore the total percentage of oxygen to the nearest tenth is 60 percent
The compound NiSO4 7H2O is magnesium sulfate heptahydrate. It is a type of inorganic salt that is commonly known as Epsom salt.
The formula for nickel II sulfate tetrahydrate is NiSO4 * 4H2O.
The formula given is mgSO4 * 7H2O. This means there are 4 oxygen atoms in MgSO4 and 14 oxygen atoms in 7H2O, giving a total of 18 oxygen atoms in the entire formula.
The compound name for 7H2O is heptahydrate.
The formula for ferrous sulfate is FeSO4.6-7H2O. (Iron Sulfate + Water) (Iron, Sulfur, Oxygen, + Hydrogen, Oxygen) No, it does not contain carbon.
1. Find the molar mass (MM) of the substances.MM FeSO4 = 151.91g+MM 7H2O = 126.11gMM FeSO4 x 7H2O = 278.02g2. Find the percent water of hydrate.Divide the mass of water by the mass of the hydrate; multiply result by 100%.126.11g278.02g x 100%Percent water of FeSO4 * 7H2O is 45.36%.Finding Molar Mass# atoms Element A x atomic mass Element A = Mass A# atoms Element B x atomic mass Element B = Mass B... etc.Add up all the mass values for the substance and you have the molar mass of the substance.
The cation of MgSO4·7H2O is Mg^2+ (magnesium ion).