molecular weight of NiSO4.7H2O is 1101.3 and it has 11 oxygens.
So percentage of oxygen = (7 x 16) / 1101.3 = 112 / 1101.3 = 0.102 or 10.2%
Oxygen is a chemical element with the symbol O and atomic number of 8. Its percentage composition in the compound NiSO4 x 7H2O is 31.3%.
62.816
44.9
The relative molecular weight of the compound nickel (II) sulphate heptahydrate NiSO4 7H2O is 280. 86. The total mass of oxygen in the compound is 176 g. Therefore the total percentage of oxygen to the nearest tenth is 60 percent
The compound NiSO4 7H2O is magnesium sulfate heptahydrate. It is a type of inorganic salt that is commonly known as Epsom salt.
The formula for nickel II sulfate tetrahydrate is NiSO4 * 4H2O.
44.80
The formula for ferrous sulfate is FeSO4.6-7H2O. (Iron Sulfate + Water) (Iron, Sulfur, Oxygen, + Hydrogen, Oxygen) No, it does not contain carbon.
Hello, Very simply, if the molar ratio is 1:1 mole, then divide the molecular weight of the anhydrous material by the hydrated one, then multiply the result by 8.753 g. Solution: NiSO4 anhydrous molecular weight is 154.75 g/mol (anhydrous) NiSO4·7H2O molecular weight is 280.86 g/mol (heptahydrate) So: 154.75/280.86 = 0.55098 The grams quantity produced from 8.753 heptahydrate is (0.55098*8.753) = 4.823 grams anhydrous NiSO4 anhydrous Best wishes AD
7h2o
MGS04 7H2O is Magnesium Sulfate . It is a heptahydrate. Epsom Salts
Mg2+