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What else can I help you with?
What is the distance traveled by an object that moves with an averace speed of 10 meters and 5 seconds?
Just divide the distance by the time. (In this case, the speed in the answer will be in meters per second.)
If you know the distance traveled and the time traveled can YOU determine an object and DIRECTION?
No, you cannot.
What is the distance traveled by an object that moves with an average speed of 6.0 meters per second for 8.0 seconds?
distance = rate x timedistance = (6.0m/sec)(8.0 sec)distance = 54 m
If a car is traveling 100 meters in 1400 seconds how fast is it traveling?
If an object is travelling 100 meters in 1400 seconds, then it is travelling (100 / 1400) or about 0.0714 meters per second.
What is the speed of an object that travels 200 meters in 25 seconds?
8ms-1
What two things must you know to determine average speed?
To determine average speed, you need to know what distance the object traveled in meters over how long it took the object to travel that distance in seconds.
What is the distance traveled by an object that moves with an averace speed of 10 meters and 5 seconds?
Just divide the distance by the time. (In this case, the speed in the answer will be in meters per second.)
If you know the distance traveled and the time traveled can YOU determine an object and DIRECTION?
No, you cannot.
What is the speed of an object that travels 100 meters in 56 seconds?
Just divide the distance by the time. This will give you the speed in meters/second. If you want to convert that to kilometers/hour instead, multiply the result by 3.6.
How can one determine the distance traveled by an object based on its acceleration?
To determine the distance traveled by an object based on its acceleration, you can use the formula: distance 0.5 acceleration time2. This formula calculates the distance traveled by an object with a constant acceleration over a certain period of time.
What is the speed of an object that travels 45 meters in 15 seconds?
The speed of the object would be 3 meters per second (45 meters ÷ 15 seconds).
What is the distance that the object travels in the first 5 seconds?
To find the distance traveled in the first 5 seconds, we multiply the average velocity by the time traveled. If the object's velocity is constant, this distance is equal to the velocity multiplied by the time.
If you know the distance of an object has traveled in a certain amount of time you can determine the?
speed of the object by dividing the distance traveled by the time taken. Speed is a measure of how fast an object is moving.
What is the average speed of an object traveling 2meters in 2 seconds then travels another 80meters duringthe next 40 seconds?
Th eobject traveled 82 meters in 42 seconds, so average speed is 82/42 = m/s = 1.95 m/s
How do you know a object's speed and velocity?
Velocity = Delta-x / Delta-t, where x is position, t is time, and "Delta" is the "Change in" operator.Velocity is a vector, so I probably should have written x as x, or x-arrow, or some other notation to indicate it was a vector quantity, but putting an arrow hat on something is a little difficult to do here, and just making it bold is kind of subtle and could be missed.Speed is the magnitude of the velocity vector.
How can one determine the distance traveled by an object using its velocity and acceleration?
To determine the distance traveled by an object using its velocity and acceleration, you can use the equation: distance initial velocity time 0.5 acceleration time2. This formula takes into account the initial velocity of the object, the time it has been traveling, and the acceleration it is experiencing. By plugging in these values, you can calculate the distance traveled by the object.
What is the formula to determine how far away is an object whose echo takes 9 seconds to return?
The formula to determine distance based on echo time is: Distance = (echo time * Speed of sound in air) / 2. Since sound travels at approximately 343 meters per second in air, if the echo takes 9 seconds to return, the distance from the object would be approximately 1543.5 meters away.
