32
-4
5f-2
It means find the value of the expression. It cannot be simplified in the way that algebraic expressions usually are.
To simplify the expression 3a^2 * 4a^5, you can first multiply the coefficients 3 and 4 to get 12. Then, you add the exponents of 'a', which gives you a total exponent of 7. Therefore, the simplified expression is 12a^7.
To simplify an expression, you can combine like terms, which contain the same variable raised to the same power. This process involves adding or subtracting the coefficients of those terms, resulting in a more concise expression. For example, in the expression (3x^2 + 5x^2), you can combine the terms to get (8x^2).
2 to the fourth x 2 = 2 to the fifth = 32
-4
5f-2
The simplify of 2 times 2 take away 2 equals 2. This is a math problem.
It means find the value of the expression. It cannot be simplified in the way that algebraic expressions usually are.
23
2+2 = 2*2 = 2^2 all simplify to 4. But there is no special name for the three expressions.
To simplify the expression 3a^2 * 4a^5, you can first multiply the coefficients 3 and 4 to get 12. Then, you add the exponents of 'a', which gives you a total exponent of 7. Therefore, the simplified expression is 12a^7.
To simplify an expression you must combine the variables and the constants. Then write the simplified version of the expression so that the expression isn't solved, just simplified. 1a+2(a+5)=2a+7
To simplify an expression, you can combine like terms, which contain the same variable raised to the same power. This process involves adding or subtracting the coefficients of those terms, resulting in a more concise expression. For example, in the expression (3x^2 + 5x^2), you can combine the terms to get (8x^2).
To simplify the expression (\frac{3^{-4} \cdot 2^3 \cdot 3^2}{2^4 \cdot 3^n}), first combine the powers of 3 in the numerator: (3^{-4 + 2} = 3^{-2}). The expression becomes (\frac{3^{-2} \cdot 2^3}{2^4 \cdot 3^n}). Next, simplify the powers of 2: (\frac{2^3}{2^4} = 2^{-1}). Thus, the simplified expression is (\frac{2^{-1} \cdot 3^{-2}}{3^n} = \frac{2^{-1}}{3^{n+2}}).
i^1=i i^2=-1 i^3=-i i^4=1 and so forth 15 divided by 4 leaves a remainder of 3 i^3=-i