print macro msg lea dx,msg movah,09h int 21h endm read macro n,j1,j2 mov cx,0ah j1:mov ah,01h int 21h cmpal,0dh je j2 sub al,30h mov bl,al mov ax,n mul cx xor bh,bhadd ax,bx mov n,axjmp j1 j2 :nop endm .model small .stack 100h .data msg1 db 10,13,'Enter the 1st number: $' msg2 db 10,13,'Enter the 2nd number: $' msg3 db 10,13,'The Sum= $' num1 dw 0 num2 dw 0 .code main proc mov ax,@data movds,ax print msg1 ;reading 1st multidigit number read num1,jump1,jump2 print msg2 ;reading 2nd multidigit number read num2,jump3,jump4 ;finding sum mov ax,num1 add ax,num2 ;printing number mov bx,000ah xorcx,cx ;push into stack p1:xordx,dx div bx pushdx inc cx cmp ax,0000h jne p1 print msg3 ;pop from stack display:popdx add dl,30h movah,02h int 21h loop display movah,4ch int 21h main endp end
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It can be called:* Multidigit * Greater or equal to ten
A group of three digits separated by commas in a multidigit number is typically referred to as a "thousands separator." This format is used to enhance readability by breaking large numbers into manageable parts, such as 1,000 or 1,000,000. The commas indicate the transition between thousands, millions, and so on, helping to distinguish the value of each segment.
You can add 3 numbers (or any quantity of numbers) and get a sum.
You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).
you do not do anything when you add numbers with exponents. you just figure out the answer. it is only if you multiply numbers with exponents, where you add the exponents..