Divide it by three.
times it by 1.5 You can also multiply it by 3 and divide the answer by 2. The works because 1 and 1/2 = 3/2.
Calculate the LCM of 2, 3, 4, 5, 6 and add 1 to get the answer: 61
3 and a half
1 / mass of a proton = avogadro's number 1 / mass of a proton = avogadro's number
That is basically a cubed root. If you know the cubes (1, 8, 27, 64, 125, ...) then you can estimate the value of n(1/3) where n = any number.
(4^3)-(3^3)-(9+1)
In HIO2, the oxidation number of hydrogen is +1 and oxygen is -2. To calculate the oxidation number of Iodine (I), you would set up the equation: (oxidation number of I) + 2(-2) + 1 = 0 (overall charge of the compound). By solving this equation, you can determine that the oxidation number of I in HIO2 is +3.
The oxidation number for N in NH2CONH2 is -3. This is because hydrogen atoms have an oxidation number of +1 each, and oxygen atoms have an oxidation number of -2. By using these values, we can calculate the oxidation number for nitrogen.
times it by 1.5 You can also multiply it by 3 and divide the answer by 2. The works because 1 and 1/2 = 3/2.
how do you calculate 1/3 of £8.31
Calculate the LCM of 2, 3, 4, 5, 6 and add 1 to get the answer: 61
divide it by 3
3 and a half
divide it by the denominator. which would be three.
There are 4 quarters in 1 dollar. To calculate the number of quarters in 1 and 3/4, you first convert 1 dollar to quarters (4 quarters), then add the additional 3 quarters for a total of 7 quarters in 1 and 3/4 dollars.
1
A subtle point is that the remainder is always a positive number. So -7 divided by 3 is -3, remainder 2 (rather than -2, remainder -1). This is important for the date of Easter because we must often calculate the remainder when dividing into a negative number. Since in that case we are not interested in the quotient it is sufficient to calculate the negative remainder and then simply add to it the number we were dividing by. So -11 mod 3 may be calculated as: -11 divided by 3 is -3, remainder -2, so the number required is -2 + 3 = 1.