First of all you need to observe maximum current at various possible supply condition (i. e. 220VAC to 260VAC). Then check the inrush current for the equipment. When you start an high power device then it draws 4 times more current than usual. Your fuse should also take care of inrush current.
For example: if maximum possible current is 500mA then your inrush current may go upto 2A. Thus if you put a fuse of 600mA then everytime you turn on the device, it may burn the fuse. So the suitable fuse for such condition is 2A
watts Divided by Volts = amps
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The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.
Find the wire from the secondary of the transformer. If it's a step-down transformer the thicker wire is the secondary. Measure its diameter in inches and calculate its cross-section area in square inches. The current rating for transformer wire is 1000 amps per square inch, or 1.55 amps per square mm.
No such thing as a 5V fuse. There is a 5 Amp fuse. These are availableat an auto parts store.
watts Divided by Volts = amps
To calculate the fuse rating level, you typically want to choose a fuse that is slightly higher than the full-load current to avoid nuisance tripping. For a full load of 4 amps, you could choose a fuse rating of 5 or 6 amps.
A: The VA rating is there 6v/a the power fuse to blow is 6watts. 050a fuse
To calculate the fuse rating for a 600 watt appliance on a 220 volt supply, you can use the formula: Fuse rating = (Power/Voltage). In this case, it would be 600 watts / 220 volts, which equals approximately 2.73 amps. Therefore, you would need a 3 amp fuse for the 600 watt appliance on a 220 volt supply.
It is ok to use a fuse with a higher amperage rating and not ok to use a fuse with a smaller amperage rating why?
The current rating is 2A (2 amps).
Using a fuse correctly rated for current but "overrated" for voltage does not present a problem. Current ratings are critical safety issues, and fuses should be replaced with those of the same current rating. But using a fuse with an identical current rating but a higher voltage rating is not a problem. The reason for that lies in what the voltage rating of a fuse is. Fuses are given a voltage rating to state a maximum voltage in a circuit that they are designed to protect. And the voltage rating has nothing to do with the "normal" operation of the fuse. The fuse carries current when it operates normally, but when something happens and excessive current flows, the fusible link heats up and opens. This is where the voltage rating comes into play. It is possible that a fuse can arc through when it fails. It is the voltage rating that stands in the way of this. As long as the voltage rating of a circuit is not beyond the voltage rating of the fuse, that fuse will fail safely when it fails. It is acceptable to use a fuse of an equal current rating but a higher voltage rating when replacing a fuse that has failed.
To calculate the minimum fuse rating needed for a 36W bulb on a 12V circuit, divide the wattage by the voltage (36W / 12V = 3A). Therefore, a minimum 3A fuse would be sufficient for a 36W bulb on a 12V circuit.
A fuse is given a various rating (strength). For instance, a home appliance (washing machine, etc) would usually have a fuse with a 13 amp rating. While a low powered lamp would only merit a 2 or 5 amp fuse rating. It is important to use a fuse of the correct rating in amps for each electrical appliance.
Each fuse has its own rating. It will be marked on the fuse somewhere.
A current rating of a fuse is designed to open a circuit at a specific current flow. This rating is imprinted on the fuse and lets you know what the maximum amount of current the fuse is designed to open at. A fuse is in the circuit to protect the conductor that the current flows through. Never over fuse a conductor's current carrying capacity.
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