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I will base the answer on the assumption you mean the 12-sided 50-cent coin.

A first approximation will assume that the coin is round, and use half a line that connects two opposing vertices as the diameter d, and then the area is pi*d^2/4. The diameter being 31.51 mm, we get 7.79 cm2 A more accurate answer will consider the coin as a regular dodecagon, that is 12 isosceles triangles whose long side's length is the circle's radius i.e. 15.25 mm, and each have a top angle of 360/12 degrees = 30 degrees. The formula in the links gives here

3*d^2/4 = 7.4466 cm2

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Q: How do you calculate the area of an Australian 50 cent coin?
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