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What is the formula for the density of a truncated cone?
Density = Mass/[(1/3*pi*h) * (R12 + R22 + R1*R2)] where h is the height of the frustum, and R1 and R2 are the radii of the two circular sections.
What is the work and answer of 689 divided by 23?
29.9565
Why do chiller's using CFC-11 and HCFC-123 require purge units?
These refrigerants have higher boiling points than say R12 or R22. Thus when a machine using them operates the low side will run in a vacuum. So any low side leak points will suck in air rather than leak refrigerant out. A purge unit constantly samples the condenser gas and removes the air and water vapor which has been pulled in at these leaking points and periodically releases them to atmosphere while it condenses any refrigerant vapor picked up in the sample mix to a liquid and returns it to the machine.
How do you find the area for a frustum cone?
V = 1/3πh ( R12 + R22 + R1R2 )where π is 3.14159265..., and R1, R2 are the radii of the two bases.
What is the formula for finding the Surface Area of a frustum of a cone?
Lateral Surface Area = π(r1 + r2)s = π(r1 + r2)√((r1 - r2)2 + h2)Top Surface Area = πr12Base Surface Area = πr22Total Surface Area = π(r12 + r22 + (r1 * r2) * s) = π[ r12 + r22 + (r1 * r2) * √((r1 - r2)2 + h2) ]
