By using Pythagoras' theorem.
Let the two points be (a,b) and (c,d). Then the distance between D= sqrt [ (a-c)^2 + (b-d)^2] where ^2 means squared.
The distance between the opposite vertices is the same.
1.414
The absolute value of the difference of their coordinate (if it is in one dimension).
It is s*√3, easily proved using Pythagoras's theorem.
Let the two points be (a,b) and (c,d). Then the distance between D= sqrt [ (a-c)^2 + (b-d)^2] where ^2 means squared.
The distance between the opposite vertices is the same.
Not necessarily. The longest distance between two points in a triangle is the distance between the vertices that are farthest apart. This can be between any two vertices, not just those connected by the longest side of the triangle.
Use the distance formula to calculate the distances between the three vertices. If they are all different, the triangle is scalene, if only two are the same, the triangle is isosceles, and if they are all the same, the triangle is equilateral.
The fork lateral dimension is adjustable and usually this range is between 300mm to 1200mm.
the foci (2 focal points) and the distance between the vertices.
of course you can
1.414
The C std::distance function can be used to calculate the distance between two iterators in a container by providing the starting and ending iterators as arguments. The function returns the number of elements between the two iterators, representing the distance.
The absolute value of the difference of their coordinate (if it is in one dimension).
The focal length formula used to calculate the distance between the focal point and the lens in optical systems is: frac1f frac1do frac1di where: ( f ) is the focal length of the lens ( do ) is the object distance (distance between the object and the lens) ( di ) is the image distance (distance between the image and the lens)
It is 51 - (-11) = 62.