First, we determine the total number of five card hands possible. Since there are 52 cards, we simply pick the first card 52 ways, then the second card 51 ways, then the third card 50 ways, then the fourth card 49 ways, and finally the fifth card 48 ways. This gives a total of 52*51*50*49*48. Since the order that we pick the cards is unimportant, we divide this total by the number of ways of permuting five objects, which is 5! = 120. So, the total becomes 52*51*50*49*48/120 = 2598960. Note this is just (52 choose 5).
Now that we know the number of possible hands, we simply divide the number of royal flushes (4) by the above 2598960:
4/2598960 = 0.000001539, the probability of getting a royal flush in the first 5 cards off the deck.
Of course, depending on the type of Poker being played, the probability will differ from this value. Omaha has a higher probability than Texas Hold'em, which has a higher probability than calculated above. Wild cards can drastically change the probability. If every card in the deck is wild, then the probability is 1 (if 5 of a kind isn't allowed) or 0 (if 5 of a kind is allowed).
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I will assume you numbers are correct, and the odds of NOT getting a royal flush is 649740 to 1, then the odd of a royal flush is the reciprocal of that. When we speak of odds in probability it has a very specific meaning. If P is the probability of an even , then the odds in favor of P are P/(1-P). For example, the odds of getting a 6 when we throw a die is not 1/6, it is 1/6 divided by 1-(1/6) or 1/6 divided by 5/6 which is 1/5 or 1 in 5. The odds of not getting a 6 is 1/(1/5)=5 to 1 So your given odds are 649740/1 and the odd of getting the royal flush are 1/649740.
With 5 cards: Straight Flush: approx 72,192 to 1 Royal Flush: 649,740 to 1 With 6 cards: Straight Flush: approx 12293 to 1 Royal Flush: 108289 to 1 With 7 cards: Straight Flush: approx 3590 to 1 Royal Flush: 30939 to 1
The answer depends on what you mean by "do". Does it mean calculate individually, calculate the probability of either one or the other (or both), calculate the probability of both, calculate some function of both (for example the sum of two dice being rolled)?
Bayesian probability ; see related link .
this is for 5-card poker (4*2^5) which gives you 128, that's your m devide it by n, which is the possibilities of hand draws (8C5) so it will be 128/1712304 and that's your answer.00007547