Messure it,
-- Measure or calculate the length of one side. -- Measure or calculate the length of another side. -- Measure or calculate the length of the only remaining side. -- Add the three numbers. The sum is the perimeter of the triangle.
If you know any two sides of a right triangle, you can calculate the third by Pythagoras' Theorem.If you know any two sides of a right triangle, you can calculate the third by Pythagoras' Theorem.If you know any two sides of a right triangle, you can calculate the third by Pythagoras' Theorem.If you know any two sides of a right triangle, you can calculate the third by Pythagoras' Theorem.
It depends on what information you do have.
What is the unit weight of aluminium section and how its calculate
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This is impossible, as a hypotenuse is only found on a right triangle.
There are always 3 edges on a triangle, otherwise it would not be a triangle.
Messure it,
you split your shape in half, (The rectangle and the triangle), by putting a line through it and then calculate the area of the rectangle and then calculate the area of the triangle, half the area of the triangle then add the area of the triangle and the rectangle together!Then you should have your answer!
-- Measure or calculate the length of one side. -- Measure or calculate the length of another side. -- Measure or calculate the length of the only remaining side. -- Add the three numbers. The sum is the perimeter of the triangle.
If you know any two sides of a right triangle, you can calculate the third by Pythagoras' Theorem.If you know any two sides of a right triangle, you can calculate the third by Pythagoras' Theorem.If you know any two sides of a right triangle, you can calculate the third by Pythagoras' Theorem.If you know any two sides of a right triangle, you can calculate the third by Pythagoras' Theorem.
The perimeter of a triangle does not provide sufficient information to calculate its area.
The method depends on the information that you have.
It depends on what y is.
It depends on what information you do have.
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