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First Left hand of decimal

1*(2^4 )+ 0*(2^3 )+ 0*(2^2) + 1*(2^1) + 1*(2^0) = 19

Now right side of decimal is,

0*(2^-1) + 1 *(2 ^-2) = 1/4 = .25

So 19.25 is required decimal

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What is the binary coded decimal of 79?

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In the following write the binary number in base 10. 1001111 base 2?

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