how do you construct a triangle which has a perimeter of 120 and the base angles abc be 30 and 45 degrees
Construct an equilateral triangle which will have 3 equal interior angles of 60 degrees and 3 equal exterior angles of 120 degrees
draw a base and use this to draw an equilateral triangle each angle of an equilateral triangle adds up to 60 degrees. To have an angle of 120 degree use this angle and then draw another side of a triangle next to it to get a 120 degree angle.
use a protractor and a ruler
Not too sure of the question but an equilateral triangle has 3 equal sides, 3 equal interior angles of 60 degrees and 3 equal exterior angles of 120 degrees
how do you construct a triangle which has a perimeter of 120 and the base angles abc be 30 and 45 degrees
Construct an equilateral triangle which will have 3 equal interior angles of 60 degrees and 3 equal exterior angles of 120 degrees
Construct an equilateral triangle because each of its 3 exterior angles measures 120 degrees
60 degrees
120 degrees = 2.0944 radians.
-120 degrees = ~-2.0944 radians
120 degrees Celsius is equivalent to 248 degrees Fahrenheit.
draw a base and use this to draw an equilateral triangle each angle of an equilateral triangle adds up to 60 degrees. To have an angle of 120 degree use this angle and then draw another side of a triangle next to it to get a 120 degree angle.
use a protractor and a ruler
The bond angle of BF2 is 120 degrees.
120 degrees is 1/3 of a circle.
120 degrees F equates to 48.9 degrees Celsius.