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In any number base, the place values are as follows: If the base is B, then:

. . . . B³ B² B¹ Bº, so for decimal (B = 10, we have [for a 3 digit number]: 10², 10¹, 10º which is the familiar 100, 10, 1 place values.

For a 3-digit number[143] in base five, it is 5² 5¹ 5º, so we have 1*5² + 4*5¹ + 3*5º = 1*25 + 4*5 + 3*1 = 25 + 20 + 3 = 48 {base ten}.

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12y ago
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Q: How do you convert 143 base 5 to decimal form?
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