Divide the number by 5, and the remainder in that division is the 'ones' (50) digit. Take that quotient (without the remainder) and divide by 5. The remainder is the 'fives' (51) digit. Continue dividing until you have zero, with a remainder and that will be the leftmost digit.
Example 27 (base ten) to base 5:
27 / 5 = 5, remainder 2
5 / 5 = 1, remainder 0
1 / 5 = 0, remainder 1
so 102 (base 5) is the same as 27 (base 10). You can check: 1 is in the (52=25) place, and the 2 is in the 'ones' place.
So (1*25) + (0*5) + (2*1) = 27
Convert the base 10 numeral to a numeral in the base indicated. 503 to base 5
Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.
1225 = 1 x 52 + 2 x 5 + 2 = 3710
1D.12516
101.101 base 2
Convert the base 10 numeral to a numeral in the base indicated. 503 to base 5
Since 52 = 25, and twice 25 is 50, the answer is 200.
To convert a number from base 5 to base 10, you multiply each digit by 5 raised to the power of its position from the right, starting at 0. In this case, for the number 43 base 5, you would calculate (4 * 5^1) + (3 * 5^0) = (4 * 5) + (3 * 1) = 20 + 3 = 23 base 10. Thus, 43 base 5 is equal to 23 base 10.
142120
Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.
Commonly numbers are base 10 already.
1225 = 1 x 52 + 2 x 5 + 2 = 3710
10011110 base 2 = 9E base 16
1D.12516
The answer will depend on what base the given number is in!
101.101 base 2
Decimal number 310 is equivalent to (1234) to the base 6