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Not sure, but a thought that came up is

by a combination of known equations:

(1) DT=DQ/mc,

DT=Difference in temperature (Kelvin)

DQ=Difference in heat (Joule)

m=mass (kg)

c=specific heat (J/K*kg)

(the increase in temperature is equal to the transfered heat divided by the mass of the object and its specific heat).

(2) 1J=1W* 1s

J=joule

W=watt

s=second

By inserting (2) in (1) you get the relation between watt and celcius (Celcius=Kelvin-273).

Hope this could be helpful..

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16y ago

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Q: How do you convert watt into Celsius?
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