The digit 6 is not a cube of any whole number. 1*1*1=1 2*2*2=8 3*3*3=27. The actual "cube root" of 6 = 1.817120593
2 out of 3
its is likely 2/3 or 1/6
3/6 or 1/2
It is 1/2 if it is a fair number cube which is rolled once.
The digit 6 is not a cube of any whole number. 1*1*1=1 2*2*2=8 3*3*3=27. The actual "cube root" of 6 = 1.817120593
cube of 1, cube of 2,cube of 3, cube of 4, cube of 5
2/6=1/3
Because the cube of a positive number is positive and the cube of a negative number is negative.-------------------------------------------------------------------------------------------------------------------------------Every number has THREE cube roots. However, (at least) two of the three are complex numbers.For example, the cube roots of 8 are 2, (-1 + √3 i) and (-1 - √3 i) with i² = -1:2³ = 2 × 2 × 2 = 8(-1 + √3 i)³ = (-1 + √3 i)(-1 + √3 i)(-1 + √3 i)= (-1 + √3 i)((-1)² - 2√3 i + 3i²)= (-1 + √3 i)(1 - 2√3 i -3)= (-1 + √3 i)(-2 - 2√3 i)= (-1 + √3 i)(-1 - √3 i)2= ((-1)² - 3i²)2= (1 + 3)2= 4 × 2 = 8(-1 - √3 i)³ = (-1 - √3 i)(-1 - √3 i)(-1 - √3 i)= (-1 - √3 i)((-1)² + 2√3 i + 3i²)= (-1 - √3 i)(1 + 2√3 i -3)= (-1 - √3 i)(-2 + 2√3 i)= (-1 - √3 i)(-1 + √3 i)2= ((-1)² - 3i²)2= (1 + 3)2= 4 × 2 = 8
It is 1/2.
A perfect cube is the cube of an integer (whole number). This means that, for n to be a perfect cube, n = x3, x∈ℤ Eg. ±1 [=(±1)3], 8 [=(±2)3], ±27 [= (±3)3], etc.
2 out of 3
The three prime numbers on the cube are: 2 3 and 5 so the probability is 3/6 or 1/2 simplified
To find the cube root of a number, enter the number followed by ^(1/3).To find the cube root of a number, enter the number followed by ^(1/3).To find the cube root of a number, enter the number followed by ^(1/3).To find the cube root of a number, enter the number followed by ^(1/3).
its is likely 2/3 or 1/6
If the negative number is "-a", then you can say the cube root is "-(cube root of a)" Because if you cube a negative number, you get a negative number. So if you cube root a negative number, you get a negative number. Ex) cube root of -8 = -2 Because (-2)^3 = -8 But if you want to find the complex cube roots, you can make an equation: "x^3=-a" or "x^3+a=0" We know one of the roots is "-(cube root of a)" so you can factor the equation by (x+(cube root of a)) And then you use the quadratic formula for the quadratic equation you're left with. Ex) x^3=-8 or x^3+8=0 Since -2 is a root, factor it by (x+2) x^3+8=(x+2)(x^2-2x+4) Using the quadratic formula, you get "1+i√3" and "1-i√3" Therefore the three cube roots of -8 is <"-2", "1+i√3", "1-i√3">
The number 27 has a cube root of 3, which is 2 (the smallest prime) plus 1.