If you're able to get around in Calculus, then that derivation is a nice exercise
in triple integration with polar coordinates. If not, then you just have to accept
the formula after others have derived it.
Actually, the formula was known before calculus was invented/discovered. Archimedes used the method of exhaustion to find the formula.
Formula for volume of a sphere = 4/3*pi*radius3 measured in cubic units.
me...
The volume for a sphere is: 4πr3 3 the π is pie (3.14)
Because when working out volumes the answer is given in cubic units and the radius in the formula for finding the volume of a sphere is cubed: Volume of a sphere in cubic units = 4/3*pi*radius3
Volume of a sphere = 4/3*pi*radius3 in cubic units.
Formula for volume of a sphere = 4/3*pi*radius3 measured in cubic units.
Volume=(4/3)π(radius of sphere)^3
me...
The volume for a sphere is: 4πr3 3 the π is pie (3.14)
It depends on the shape. The formula for the volume of a sphere is quite different from that for the volume of a cube.
Use the formula for volume to solve for the radius of the sphere and then plug that radius into the formula for the surface area of a sphere.
Because when working out volumes the answer is given in cubic units and the radius in the formula for finding the volume of a sphere is cubed: Volume of a sphere in cubic units = 4/3*pi*radius3
Volume of a sphere = 4/3*pi*radius3 in cubic units.
The formula for the volume of any sphere isVolume = ( 4/3 pi ) x (cube of the radius)
The volume of a sphere is given by the formula V =⁴⁄ ₃πr3The volume of a sphere with radius 7cm = ⁴⁄ ₃π73 = 1436.76 cm3 (to 2 dps)
Volume = 4/3*pi*radius3
Volume of a sphere = 4/3*pi*radius3 and measured in cubic units