Consider a ray of light AB, parallel to the principal axis, incident on a spherical mirror at point B. The normal to the surface at point B is CB and CP = CB = R, is the radius of curvature. The ray AB, after reflection from mirror will pass through F (concave mirror) or will appear to diverge from F (convex mirror) and obeys law of reflection, i.e., i = r.
From the geometry of the figure,
If the aperture of the mirror is small, B lies close to P, BF = PF
or FC = FP = PF
or PC = PF + FC = PF + PF
or R = 2 PF = 2f
or F=R/2
or 2F=R
Hope this helps............
This involves the rate of change of the unit tangent vector. Deriving the curvature starts with the equation of a circle. Then three equations that force the collocation circle to go through the three points and on the curve must be written down. Then solve for a, b, and r.
I derive that this question needs to be moved.
The noun forms of the verb to derive are deriver, derivation, derivative, and the gerund, deriving.
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Here is the derivation on dsplog: http://www.dsplog.com/2008/07/17/derive-pdf-rayleigh-random-variable/
In a concave mirror, when an object is placed between the focus and the center of curvature, the image formed is real, inverted, and enlarged. To derive the mirror formula, use the mirror formula: 1/f = 1/v + 1/u, where f is the focal length, v is the image distance, and u is the object distance. The magnification formula is: M = -v/u, where M is the magnification, v is the image distance, and u is the object distance.
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For a convex mirror, the focal length (f) is half the radius of curvature (R) of the mirror. This relationship arises from the mirror formula for convex mirrors: 1/f = 1/R + 1/v, where v is the image distance. When the object is at infinity, the image is formed at the focal point, and the image distance is equal to the focal length. Hence, 1/f = -1/R when solving for the focal length in terms of the radius of curvature for a convex mirror.
1 coulomb= 3*109 statcoulomb
s=b/a for n port network in matrix form[b]=[s]*[a].there is also relation between z matrix in s matrix.
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This involves the rate of change of the unit tangent vector. Deriving the curvature starts with the equation of a circle. Then three equations that force the collocation circle to go through the three points and on the curve must be written down. Then solve for a, b, and r.
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2^(n^2+n)/2 is the number of symmetric relations on a set of n elements.
Derive the castiglino's theorem
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I derive that this question needs to be moved.