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It depends on the precise nature of the coder and there are many possibilities. Here are three:
A: f(x) = 2x
B: f(x) = 4*(x - 1)
C: f(x) = 2*(x2 - 3x + 4)
The simplest of these is f(x) = 2x.
In that case the decoder is y = ln(x)/ln(2) where ln is the natural logarithm. Logs to base 10, or any other base can also be used and, if the chosen base is 2, then the decoder becomes:
y = log2(x)
What else can I help you with?
How many outputs are possible for 4 input decoder?
A 4-input decoder can produce (2^n) outputs, where (n) is the number of inputs. For a 4-input decoder, (n = 4), so the number of possible outputs is (2^4 = 16). Therefore, a 4-input decoder can generate 16 distinct output lines based on the 4 input combinations.
How do you make 6 to 64 decoder using four 4 to 16 and one 2 to 4 decoder?
To create a 6 to 64 decoder using four 4 to 16 decoders and one 2 to 4 decoder, first, separate the 6 input bits into two groups: the upper 2 bits (let's call them A5 and A4) and the lower 4 bits (A3 to A0). Use the 2 to 4 decoder to decode the upper 2 bits, which will select one of the four 4 to 16 decoders. Then, connect the lower 4 bits to all four 4 to 16 decoders. The selected 4 to 16 decoder will activate one of its 16 outputs based on the lower 4 bits, resulting in a total of 64 outputs from the combination of the decoders.
Is 4 and 2 thirds - 2 thirds greater than 4 eighths plus 3 and 2 eighths?
4 and 2/3 - 2/3 = 4 4/8 + 3 and 2/8 is the same as 3 + 2/4 +1/4 which is 3 and 3/4 4 > 3 + 3/4 (aka, yes)
What is -2 wholes 3 over 4 minus 1 over 4?
-2 3/4 - 1/4 = -(2 3/4 + 1/4) = -[2 (3+1)/4] = -(2 4/4) = -(2 + 1) = -3 or -2 3/4 - 1/4 = - (4*2 + 3)/4 - 1/4 = -11/4 - 1/4 = (-11 - 1)/4 = -12/4 = -3
What is the subset of set A12345?
There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .
How do you make 3 8 decoder?
Use two 2-4 decoders.
How many outputs are possible for 4 input decoder?
A 4-input decoder can produce (2^n) outputs, where (n) is the number of inputs. For a 4-input decoder, (n = 4), so the number of possible outputs is (2^4 = 16). Therefore, a 4-input decoder can generate 16 distinct output lines based on the 4 input combinations.
How can one make 6-to-64 decoder with the help of 4-to-16 decoders?
Oh, dude, making a 6-to-64 decoder with 4-to-16 decoders is like building a tower of Legos with some missing pieces. You just gotta cascade the 4-to-16 decoders in a way that each output of the 6-to-64 decoder corresponds to a unique combination of inputs from the 4-to-16 decoders. It's kinda like solving a puzzle, but with electronic components.
How do you make 6 to 64 decoder using four 4 to 16 and one 2 to 4 decoder?
To create a 6 to 64 decoder using four 4 to 16 decoders and one 2 to 4 decoder, first, separate the 6 input bits into two groups: the upper 2 bits (let's call them A5 and A4) and the lower 4 bits (A3 to A0). Use the 2 to 4 decoder to decode the upper 2 bits, which will select one of the four 4 to 16 decoders. Then, connect the lower 4 bits to all four 4 to 16 decoders. The selected 4 to 16 decoder will activate one of its 16 outputs based on the lower 4 bits, resulting in a total of 64 outputs from the combination of the decoders.
How can you design 4-to-16 decoder with five 2-to-4 decoder?
It turned out to be very easy))) But I was thinking for a while to solve the problem... )))Ok. Lets say we have inputs S3..S0. Let S3 and S2 go to inputs of each of FOUR of decoders; and S1 with S0 go to the inputs of the FIFTH decoder. The four outputs of the FIFTH decoder go to enable lines of the four decoders. Voila! It might be confusing, but just draw the whole thing and you'll see. Now you just need to enable the fifth decoder... HA-HA!
Impliment 8 into 256 decoder using decoder circuit?
8:256 decoder circuit can be implemented by using 4:16 decoder circuit
What are types of software design?
1. data design 2. architectural design 3. process design 4. interface design 5. procedural design
Draw the logic diagram of 2 to 4 line decorder with only nor gates include an enable input?
draw the logic diagram of 2 to 4 line decoder decoder using nor gates include enable input
How can I program 4 x 16 decoder in VHDL?
There are many different optional codes. Here are brought three of them.1st - 2:4 decoder using "enable" :entity DECODER isport (A, B, Enable : in std_logic ;Out : out std_logic_vector(3 downto 0));end DECODER;architecture ARC.DECODER of DECODER isbeginOut(0)
Why does your LCD not isplay the full picture from your decoder It is zoomed by default and I cant reset it?
Oh I had to change the settings on the decoder to send the signal as 4:3 instead of 16:9
How do you do the decoder on Poptropica?
Click on the decoder 4 times the type in 130928:):):):):) I hope this helped:):):)
Show how many 2-to-4 decoders are required to build a 6-to-64 decoder?
56
