It depends on the precise nature of the coder and there are many possibilities. Here are three:
A: f(x) = 2x
B: f(x) = 4*(x - 1)
C: f(x) = 2*(x2 - 3x + 4)
The simplest of these is f(x) = 2x.
In that case the decoder is y = ln(x)/ln(2) where ln is the natural logarithm. Logs to base 10, or any other base can also be used and, if the chosen base is 2, then the decoder becomes:
y = log2(x)
4 and 2/3 - 2/3 = 4 4/8 + 3 and 2/8 is the same as 3 + 2/4 +1/4 which is 3 and 3/4 4 > 3 + 3/4 (aka, yes)
-2 3/4 - 1/4 = -(2 3/4 + 1/4) = -[2 (3+1)/4] = -(2 4/4) = -(2 + 1) = -3 or -2 3/4 - 1/4 = - (4*2 + 3)/4 - 1/4 = -11/4 - 1/4 = (-11 - 1)/4 = -12/4 = -3
There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .
1 Requirements Review 2 Low Level Design Review 3 High Level Design Review 4 Code Walk-Thru
((3/3)/4)*2 = (1/4)*2 = 2/4 = 1/2.
for design 6-to-64 decoder we need four 4-to-16 decoders for last stage and one 2-to-4 decoder for selecting each of them..
Use two 2-4 decoders.
It turned out to be very easy))) But I was thinking for a while to solve the problem... )))Ok. Lets say we have inputs S3..S0. Let S3 and S2 go to inputs of each of FOUR of decoders; and S1 with S0 go to the inputs of the FIFTH decoder. The four outputs of the FIFTH decoder go to enable lines of the four decoders. Voila! It might be confusing, but just draw the whole thing and you'll see. Now you just need to enable the fifth decoder... HA-HA!
1. data design 2. architectural design 3. process design 4. interface design 5. procedural design
8:256 decoder circuit can be implemented by using 4:16 decoder circuit
draw the logic diagram of 2 to 4 line decoder decoder using nor gates include enable input
There are many different optional codes. Here are brought three of them.1st - 2:4 decoder using "enable" :entity DECODER isport (A, B, Enable : in std_logic ;Out : out std_logic_vector(3 downto 0));end DECODER;architecture ARC.DECODER of DECODER isbeginOut(0)
Oh I had to change the settings on the decoder to send the signal as 4:3 instead of 16:9
Click on the decoder 4 times the type in 130928:):):):):) I hope this helped:):):)
56
To create a decoder with symbols, you need to assign a unique symbol to each input combination of the decoder. For example, in a 2-to-4 decoder, you could use symbols like A, B, C, and D to represent the output signals corresponding to the input combinations. By using symbols that are easy to understand and differentiate, you can effectively represent the decoder's logic and functionality.
1. Investigate 2. Design 3. Make 4. Evaluate