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If length = L and width = W then
area A = L*W and perimeter P = 2(L+W).
So, from the area equation, L = A/W
Substituting this in the equation for P gives P=2(A/W + W) = 2A/W + 2W
Then multiplying through by W gives PW = 2A + 2W2
or, in standrad form, 2W2 - PW + 2A = 0
Then W = 1/4*[P +/- sqrt(P2 - 16A)]
The two solutions of this quadratic will be W and L.
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How do you determine length if given the perimeter and width?
multiply the width by 2 and then subtract that to the perimeter then divide the answer by 2 to get the length
How can you calculate the length of a rectangle if the perimeter and the width are given?
Because the perimeter is lenght + length +width +width, you do perimeter - double the width, and then halve the remaining number. that should give you the length.
How do you find the length of a rectangle if the perimeter is 40 and the width is 2inches?
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
What is the width if the perimeter and length are given?
The width would be: P - (L*2) = W*2 Perimeter = P Length = L Width = W
How do you find the length and width of rectangle when given the perimeter but not the width or length?
by appying 2l+2w
