f(x)=(x(x-1)^.5) dx
Look at the equation in pieces. Piece A is x, and Piece B is ((x-1)^.5)dx
The derivative will be the derivative of piece A times Piece B all added to the derivative of piece B times Piece A. So we will need to find the derivative of each individual piece to find the solution.
The derivative of Piece A is 1.
Use the u-substitution method of differentiation to find the derivative of Piece B.
Have u=(x-1), causing du to equal dx. The derivative of (u^.5) is dx/2(u^.5)
Substitute the original piece back in to give you 1/2(x-1)^.5
So the derivative of the original function would be...
(1 times (x-1)^.5) + (x times (1/2(x-1)^.5) all times dx
The only thing you can really do to simplify that would be to replace the 1 in the final fraction with the x that you are multiplying it by.
The square root of minus 8 is equal to the square root of 8 times the square root of minus 1, or 2.8284i.
Two plus 3 minus 2 times 1 squared plus 4 times 16 squared minus 4 times 2 is equal to 1,019.
3u2-1
4 times 4 minus 4 minus square root of 4.
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The square root of minus 8 is equal to the square root of 8 times the square root of minus 1, or 2.8284i.
Two plus 3 minus 2 times 1 squared plus 4 times 16 squared minus 4 times 2 is equal to 1,019.
3u2-1
4 times 4 minus 4 minus square root of 4.
4 sqrt(3) is. 8 of anything, minus 4 of the same thing, always leaves 4 of them.
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If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.
the square root of b squared minus 4 times a times c
It is: (3*2)-(2*2) = 2
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x is equal to negative b plus or minus the square root of b squared minus 4 times "a" times "c" all over 2 times "a"
(3 x 2) - (2 x 2) = 2