Put a decimal point after the two digit number and add zeros after the decimal point. Then you can divide just as you always would, with the answer being less than one. For example, to divide 40 by 2000, put the decimal point after 40 and add zeros, like this: 40.00 Now divide as if it were 4000 divided by 2000, which equals 2, except that the 2 will go after the 0.0, to make 0.02
Divide the first digit by 2: 4/2 = 2 Then the second digit: 5/2 = 2.5 And then put them back together: 22.5
No it would be 2-3 digets depending on the number.
When you divide a 4-digit number by 9, the remainder can only be an integer from 0 to 8. If your answer has a remainder of 2 over 3, it suggests a misunderstanding, as remainders are whole numbers. If you're looking for a 4-digit number that leaves a remainder of 2 when divided by 9, it would be expressed as ( n \equiv 2 \mod 9 ).
23 divide 3974
For example 44/55 = 4/5 = 0.8 or 45/5 = 9 Basic stuff
Divide the first digit by 2: 4/2 = 2 Then the second digit: 5/2 = 2.5 And then put them back together: 22.5
No it would be 2-3 digets depending on the number.
you right the numbers and divide
When you divide a 4-digit number by 9, the remainder can only be an integer from 0 to 8. If your answer has a remainder of 2 over 3, it suggests a misunderstanding, as remainders are whole numbers. If you're looking for a 4-digit number that leaves a remainder of 2 when divided by 9, it would be expressed as ( n \equiv 2 \mod 9 ).
You can't tell anything about the quotient until you know whatthe divisor is going to be.-- If I divide your 4,796 by 4, the quotient is 1,199 . . . 4 digits.-- And if I divide it by 2,398, the quotient is 2 . . . . only 1 digit.
23 divide 3974
example-99/33=3
37.5
34
62
For example 44/55 = 4/5 = 0.8 or 45/5 = 9 Basic stuff
3 more than 5 is 8, so the tens digit is 8. The tens digit is,double the number of the ones digit, so divide 8 by 2 and you get 4. If you double 4 it is 8 so, the number is 84.