phi = 1.618 to 3 dp pi = 3.142 to 3 dp
7. 3.012 has 3 dp 6.2034 has 4 dp so their product has 3 + 4 = 7 dp. If there are trailing zeros, these would not normally be written and so would reduce the number of dp; the last digit is 2 x 4 = 8, which is not zero, so there will be 7 dp in their product.
Rounded off to how many decimal places (dp) !... 0.795 (3 dp) 0.80 (2dp)
The answer is 9.577 (to 3 dp).
Infinitely many. 1 + 1328 2 + 1327 and so on. Then consider numbers to 1 decimal place (dp). 1.1 + 1327.9 1.2 + 1327.8 etc. Next you can include numbers to 2 dp, 3 dp, 4 dp all the way to infinitely many dp. Next you can look at sums of 3 number, 4 number, ... infinitely many numbers.
To 4 DP, 62.1935 To 3 DP, 62.194 To 2 DP, 62.19 To 1 DP, 62.2
phi = 1.618 to 3 dp pi = 3.142 to 3 dp
To 1 dp it is 1.0; to 2 dp it is 1.00; to 3 dp it is 1.000
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0.0704
The answer is: 18.823
7. 3.012 has 3 dp 6.2034 has 4 dp so their product has 3 + 4 = 7 dp. If there are trailing zeros, these would not normally be written and so would reduce the number of dp; the last digit is 2 x 4 = 8, which is not zero, so there will be 7 dp in their product.
There are infinitely many possible answers.For example, 1, 2, 3, 4 and 37or -4, -3, -2, -1 and 57.Or you can use numbers to 1 decimal place (dp), 2 dp, 3 dp and so on.
Rounded off to how many decimal places (dp) !... 0.795 (3 dp) 0.80 (2dp)
2.476 (to 3 dp)
2.571% to 3 dp.
2'149.601522 = 2'149.602 to 3 dp