move the -10 onto the other side and swap the sign
x=3+10
x=13
*****************
My version is basically the same as above, but...
x-10=3
First you would add 10 to both sides. This balances out the fact that in the equation you are subtracting. It the equation was x+10 you would subtract 10. Add.
x-10=3
+10 +10
x=13
So your answer is that X is 13.
45.7*10-3 = 0.0457
0.006533 = 6.533e-3 or 6.533 x10^-3
0.00604
9.0 x10^-3
The new mean would be 7. The mean is the average of the data. (x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10=21 [(x1/3)+(x2/3)+(x3/3)+(x4/3)+(x5/3)+(x6/3)+(x7/3)+(x8/3)+(x9/3)+(x10/3)]/10=? [(1/3)(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)]/10=? [(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10]/3= 21/3=7
3 x10 30 x10
No, since there's no decimal point, it equals 875 or 8.75 x 10^2
It looks like an incomplete equation.
1.357 x10-3 in standard notation is: 0.001357
Yes, if x10=y.
e could either mean x10^ or 2.718. I think in this case it means x10^. THIS ANSWER WILL REQUIRE AN UPDATE.
29000000
kg x10^3
45.7*10-3 = 0.0457
2.058911321...x10^14
0x10=10 because your counting 10 0 times
0.006533 = 6.533e-3 or 6.533 x10^-3