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It is impossible to do this. The measures of all of the interior angles in a hexagon add up to 360 degrees, so for there to be four right angles the other two angles would have to be zero, which isn't possible.

Visit the Related Link below for an image. The right angles in this image are numbered. Remember that hexagons are six-sided polygons.

Q: How do you draw a hexagon with four right angles?

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no

Draw a square

No. A hexagon has 6 sides and 6 vertices (angles). A polygon with four sides and four angles is a quadrilateral.

There are many options. Here is one______|......||.......\|......./|___|

you cant because it would be a square

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no

Draw a square

No. A hexagon has 6 sides and 6 vertices (angles). A polygon with four sides and four angles is a quadrilateral.

There are many options. Here is one______|......||.......\|......./|___|

No. The definition of a rectangle is - a parallelogram with four right angles. Hexagons don't have parallel sides and they don't have right angles

Four exactly? A regular hexagon has 6. But a hexagon can have four obtuse angles. A regular hexagon can be made a lot flatter so that the two angles at the sides become acute, while the remaining 4 are obtuse.

you cant because it would be a square

This describes a rectangle. It has four sides, four right angles, and its opposite sides are parallel, but the adjacent sides are not equilateral (congruent). If a quadrilateral has four right angles, it will be either a square or a rectangle. With the four right angles, it cannot be anything else. Draw a line segment. Now draw another one at a right angle to the first one. Now draw a third line segment at a right angle from the second one, and make this one the same length as the first one. Then draw the last segment to close the figure. It will have fours sides, and it will have four right angles. It will also have two pairs of parallel sides.

If 1 or 2 of the obtuse angles are 'bent into' the hexagon then you can do it.A hexagon has 720Â° sum of interior angles. If you have 2 right angles, then that's 180Â°, leaving 540Â° to be distributed over four angles. If the two acute angles are 89Â°, then that leaves 362Â° to be divided between two angles, so at least one of these two angles will need to be greater than 180Â°. Below is my text graphics attempt of one possibility (ignore the 'dot'). Note that both of the obtuse angles are greater than 180Â°:|\_/||__.|Look at the related link to play with different angle possibilities for polygons.

Two lines that are perpendicular to each other will form four right angles which looks like a large + sign

The sum of all four angles is 360 degrees. If three of the angles were right angles then the fourth would have to be a right angle. You would then have a rectangle or a square, but not a trapezium.

No because then it would then be a square or a rectangle