Draw a square.
Add the two diagonals.
Draw lines from the midpoint of each side to the midpoint of the opposite side.
You will now have a square divided into 8 congruent [isosceles, righ-angled] triangles
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Only once, there will only be eights parts however you divide it.
by dividing by 6 .and if the eighth is whole then divide by 7 .________________________I have a different take; if I have misunderstood the question then I trust a kind contributor will delete this contribution. The questioner may be asking how to divide a square into pieces each one eighth the size of the original square. The pieces will be right triangles of equal size. They will not all be congruent with one another, however. Four will be congruent with each other, and the remaining four will be congruent with each other. Draw lines connecting opposite vertices; they will meet at the center. Then draw lines connecting the centers of opposite sides.Another way is to end up with 8 identical rectangles. Divide the width into 8 equal parts, and divide the height into 8 equal parts. For example: a square 8 inches per side. Then divide the square into 4 inch by 2 inch rectangles. There will be 8 of them.
Divide a vertical side into 8. Draw lines parallel to a horizontal side. You will have 8 horizontal strips.Divide a horizontal side into 8. Draw lines parallel to a vertical side. You will have 8 vertical strips.Divide the square in half horizontally, divide both halves horizontally and then divide them all vertically.Divide the square in half horizontally, divide both halves vertically and then divide them all vertically again.These are some. There are also methods involving diagonal divisions or L-shaped pieces.
A regular octagon has 8 equal sides
If you can draw a line 1 inch long and divide it into 8 equal parts, then each of the segments would be an eighth of an inch long