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Q: How do you draw a triangle with an area of 16 square units?

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Squares are rectangles. Draw a 2 unit square.

A right-angle triangle is half of a square or rectangle. Draw a square or rectangle and draw a line from one corner to the corner diagonally opposite. You now have two triangles of the same area.

== == 1) Draw a line segment AB of 5 units 2) Draw the perpendicular bisector CD of AB such that Cd meerts AB at C. 3) Mark off CE = 2 units on CD 4) Draw the straight line segments AE & BE. ABE is your triangle. Its base (AB) = 5 and height (CE) = 2, so its area = [base x ht] / 2 = 5 sq units

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You can't without having incomplete units.

A right-angle triangle is half of a square or rectangle. Draw a square or rectangle and draw a line from one corner to the corner diagonally opposite. You now have two triangles of the same area.

Squares are rectangles. Draw a 2 unit square.

== == 1) Draw a line segment AB of 5 units 2) Draw the perpendicular bisector CD of AB such that Cd meerts AB at C. 3) Mark off CE = 2 units on CD 4) Draw the straight line segments AE & BE. ABE is your triangle. Its base (AB) = 5 and height (CE) = 2, so its area = [base x ht] / 2 = 5 sq units

yes

Draw a straight line AB of any length x. Draw another line, parallel to AB and at a distance of 2*24/x units from it. Select any point on the second line and call that point C. Join AC and BC. Then triangle ABC will have an area of 24 square units.

YES From your start point draw a line 5 units up, from this point draw a line 5 units across, from this point draw a line 5 units down, from this point draw a line 5 units back to the start. You have drawn a square with a total perimeter length of 20 units and a area of 25 square units.

Draw a right angled triangle with legs of lengths 2 and 3 units. The hypotenuse will be sqrt(13) units.

There are many different triangles that have an area of three square inches, here's one way to draw one: Draw a rectangle whose area is six square inches (or imagine what one's dimensions would be, e.g. 6x1 or 3x2) and cut it in half diagonally to make a right triangle that has an area of three square inches.

the answer is jermil warren with a thing :)

Right triange with both sides around the 90 degrees = 4 with a right trianle the area = 1/2 * height * width (think of it as half a rectangle)