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A simple method - though not the fastest one - is to try calculating the cube of different numbers, until you find one that gets close enough.
Both this method and any other method require so much calculations that it's better to just leave such calculations to a scientific calculator. Or type a formula in Excel, for example:
=125^(1/3)
Explanation: "^" is used to raise a number to a power. Raising a number to the power 1/3 is the same as taking the cube root.
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What is the cubed root for 6967.871?
The cubed root of 6,967.871 is 19.1
What is the cubed root of x2y4?
y times the cube root of x2y
How do you evaluate -b cubed if b is five?
It is: -53 = -125
The square root cube of 216?
if you mean the cubed root, the answer is 6. i would show you the calculations but unfortunately i have no idea how to do a cubed root sign. :S :)
What are some real world examples of cube roots?
The cubed root of 27 is 3. The cubed root of 8 is 2.
What is 4 cubed evaluate to?
4 cubed is 64
What is a cubed root How do you find the cubed root?
ask your teacher
What is the cubed root for 6967.871?
The cubed root of 6,967.871 is 19.1
Cube root of 4 to power of 3?
The cubed root of 43 is 4!The cubed root of 8 (or 23) is 2
What is the cubed root of x2y4?
y times the cube root of x2y
What the square root of 36 then cubed?
The square root of 36 is 6. 6 cubed is 216.
What is the inverse operation of finding the cubed root?
The inverse of finding the cube root is cubing the number. For example, the cubed root of 27 is 3. 3 cubed, (or 33) is 27.
What is the cubed root of 4 over 9?
Improved Answer:The cubed root of 4 over 9 is 0.7631428284
How do you evaluate -b cubed if b is five?
It is: -53 = -125
What number cubed equals 343?
The cubed root of 343 is 7
The square root cube of 216?
if you mean the cubed root, the answer is 6. i would show you the calculations but unfortunately i have no idea how to do a cubed root sign. :S :)
Can a 45cm3block fit in a 50cm3 space?
The cubed root of 45 is 3.5568... and the cubed root of 50 is 3.6840... Therefore, yes
