Q: How do you expand fully and simplify x open bracket x-1 close bracket squared?

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7(a + 3) = 7*a + 7*3 = 7a + 21

3(7a - 5b) + 2(4a - 3b) Multiply the contents of each bracket by the number outside it: 21a - 15b + 8a - 6b Bring like terms together: 21a + 8a - 15b - 6b Combine like terms: 29a - 21b This cannot be simplified further.

(x2y2)3 + (x3y3)2 = 2x6y6.

7C MINUS bracket open c plus 2 bracket close equals 7c minus c minus 2 equals 6c minus 2

-(3x-4) = -3x + 4

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7(a + 3) = 7*a + 7*3 = 7a + 21

sure... I bet lots of people can simplify this... How 'bout 5x sq -15

x cubed y cubed z squared

3(7a - 5b) + 2(4a - 3b) Multiply the contents of each bracket by the number outside it: 21a - 15b + 8a - 6b Bring like terms together: 21a + 8a - 15b - 6b Combine like terms: 29a - 21b This cannot be simplified further.

(x2y2)3 + (x3y3)2 = 2x6y6.

(x-2)(x+2)= x2+2x-2x-4= x2-4

you first solve the inside of the bracket and then do the inside answer with the outside numbers.

7C MINUS bracket open c plus 2 bracket close equals 7c minus c minus 2 equals 6c minus 2

2(2*1) = 2(2) = 4

-(3x-4) = -3x + 4

I think I'm answering my own quezstion here but hey. Am I right in saying that (x+0)(x+1) Factorises to x2+ x? I think I am.

Estimating implies that the number is approximate to the desired value so any number squared that is close to the desired estimation would be considered close enough. Rounding off is a form of estimating and has a set of rules that accompany it. For simple estimating, (non-medical, hazardous items not included) like "what is the square root of 169". it would be about 13X13 or 13 squared. Get closer by finding the factors of 169. and simplify.