Q: How do you factor 18x squared yz plus 12xy squared z plus 6xyz squared?

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(x + 5y)(x + 7y)

(a + x^2)(b + y^2)

4(x+y)^2

(a + 2 - b) (a + 2 + b)

(3q + 2p)(9q + 7p)

Related questions

(x + 5y)(x + 7y)

(a + x^2)(b + y^2)

No

(6x + t)(3x + t)

(3q + 2p)(9q + 7p)

(a + 2 - b) (a + 2 + b)

4(x+y)^2

2(5c + 2d)(5c + 2d)

(a+b)(a squared-ab+b squared)

Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)

(a+b)(3b+1)

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