2(d^2 + 6d - 8)
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The GCF is 3d2, leaving 2d2 3d 4
Divide the factor into the number. If the answer is a whole number, the factor is a factor.
y = 17 - 3xy = x2 + 2x -717 - 3x = x2 + 2x -70 = x2 + 5x -24(x + 8)(x - 3) = 0 so x =-8 and x = 3y = 17 -3(-8) = 41 ==> (-8,41) endpoint of liney = 17-3(3) = 8 ==> (3,8) 2nd endpoint of lined2 = (x2 - x1)2 + (y2 - y1)2d2 = (3 - -8)2 + (41 - 8)2d2 = 112 + 332 =1(112) +(32)(112) =10(112)d = 11(sq root(10)) answer
It is a factor of 132, not a prime factor.
I believe the opposite of a factor is a multiple. It could also be a non-factor.