(2x-3)(x-1)
(2x+3)/(10x2+21x+9)Factor the quadratic expression in the denominator:(2x+3)/(5x+3)(2x+3)which becomes:1/(5x+3) or (5x+3)-1
2x2+5x+3 = (2x+3)(x+1) when factored
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
(2x - 1)(x + 3)
(x - 1)(5x + 7)
(2x-3)(x-1)
2x squared - 5x - 3 = (2x +1)(x -3)
5
(2x - 1)(5x + 8)
-x2+2x
(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
(2x+3)/(10x2+21x+9)Factor the quadratic expression in the denominator:(2x+3)/(5x+3)(2x+3)which becomes:1/(5x+3) or (5x+3)-1
2x2 + 5x = x*(2x + 5)
If that was 2x^2 + 5x + 2, it would factor to (2x + 1)(x + 2)
2x2+5x+3 = (2x+3)(x+1) when factored
7x2 -4x -5x2 +2x = 2x2 -2x