2y^2+5y+2=(2y+1)(y+2)
(x + 5y)(x + 7y)
Y=30
The question is not quite clear, do you mean -6x+3y = -18 and -10+5y = -30? If so then the solution is: -10+5y= -30 5y = -30+10 5y = -20 y = -4 Substitute the value of y into the equation -6x+3y = -18: Answer: x = 1 and y = -4
It is y = -7
2y^2+5y+2=(2y+1)(y+2)
(y+2)(y+3)
(2x + 3y)(2x + 5y)
(x + 5y)(x + 7y)
Y=30
The given expressions are: 5x + 5y = 30 3x - 5y = -30 Combine both equations to get: 5x + 3x + 5y - 5y = -30 + 30 8x = 0 Then: 8x/8 = 0/8 x = 0 Substitute that value for either of the expressions to get: 5(0) + 5y = 30 5y = 30 y = 30/5 y = 6 Therefore, the coordinates are x = 0 and y = 6.
2(5x + 3y)(2x + 5y)
The question is not quite clear, do you mean -6x+3y = -18 and -10+5y = -30? If so then the solution is: -10+5y= -30 5y = -30+10 5y = -20 y = -4 Substitute the value of y into the equation -6x+3y = -18: Answer: x = 1 and y = -4
It is y = -7
(x + 5y)(x - 3y)
(y - 1)(y - 4)
(4y - 1)(5y + 2)