x4 - x2 - 12 = (x2 + 3) (x2 - 4)And (x2 - 4) = (x + 2) (x - 2)So the original expression = (x2+ 3) (x + 2) (x - 2)
one
1/12
X4 - 144 (X2 - 12)(X2 + 12) As there is no linear term I see no further factoring.
Two thirds minus one fourth is equal to five twelfths.
x4 - x2 - 12 = (x2 + 3) (x2 - 4)And (x2 - 4) = (x + 2) (x - 2)So the original expression = (x2+ 3) (x + 2) (x - 2)
one
1/12
X4 - 144 (X2 - 12)(X2 + 12) As there is no linear term I see no further factoring.
5/6 minus 3/4 is 1/12
1/12 th
(2x - 4)(2x + 3) The key is to look for all the factor pairs of 12.
Two thirds minus one fourth is equal to five twelfths.
It is: 1/3 minus 2 and 1/4 = -23/12 or -1 and 11/12
5x2-16x+12 = (5x-6)(x-2) when factored with the help of the quadratic equation formula
four
It is x^2 -x -12 is (x+3)(x-4) when factored