(t - 3)(t^2 + 3t + 9)
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All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======
(4x - t2)= [(2√x)2 - t2] (This is now the difference of squares)= (2√x - t)(2√x + t)
n2 - 100t write t = (√t)2 = n2 - (10√t)2 = (n - 10√t)(n + 10√t)
8 - (9 - t)
28 t2 - 17 t - 3 = (7t + 1) x (4t - 3)