-((4x + 1)(x - 1))
(x + 3)(x + 2)
(3x + 1)(4x - 1)(x - 2)
1
(2x-4)(x-1) = 0
-((4x + 1)(x - 1))
4(x + 1) = 0.
x3+x2+x First, factor out the x: x(x2+x+1) Could stop there, but the rest is factor-able using imaginary numbers: x(x+.5(1+i(3).5)(x+.5(1-i(3).5), where i = (-1).5, or sqrt(-1)
That equals 1.25x. There's nothing to factor.
3(2x - 1)(x - 2)
(x + 3)(x + 2)
(3x + 1)(4x - 1)(x - 2)
(x + 3)(x + 4)
It is: (5x-1)(x-1) = 0 Therefore: x = 1/5 or x = 1 Use the quadratic equation formula
1
(2x-4)(x-1) = 0
0 because X= -1