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x^2 - 13x + 12
From the constant '12' we need two numbers, that multiply to '12' and 'add/subtract' to '13'.
So write down the factors of '12' . They are 1,12; 2,6' ;3,4'
Only '1,12' satisfies.
Set set up the brackets.
(x 12 )(x 1)
Next we need to put in the correct signs. We note that '12' is positive, so both the signs are the same. We also note that '13' is negative, so both the signs are negative.
So fully factored it becomes ( x - 12)(x - 1) ; Both signs the same (-) , both signs are negative(-).
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