x^2 - 13x + 12
From the constant '12' we need two numbers, that multiply to '12' and 'add/subtract' to '13'.
So write down the factors of '12' . They are 1,12; 2,6' ;3,4'
Only '1,12' satisfies.
Set set up the brackets.
(x 12 )(x 1)
Next we need to put in the correct signs. We note that '12' is positive, so both the signs are the same. We also note that '13' is negative, so both the signs are negative.
So fully factored it becomes ( x - 12)(x - 1) ; Both signs the same (-) , both signs are negative(-).
It is: 4(x+3)
You can factor it, if you consider that simpler.
There is no factor of the expression in the question.
(x+7)(x+12)
=3x * * * * * The correct answer is: x2 + 7x + 12 = (x + 3)(x + 4).
The other factor is 1.
12(m + 5)
12(b + 1)(b + 1)
2x+12=2(x+6)
(x + 6)(x + 2)
(3x+12)(5x+2)
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
3(3z + 4)
3(4 + q)
It is: 4(x+3)
You can factor it, if you consider that simpler.
There is no factor of the expression in the question.